Alphabetical Series Set 1 | Reasoning

Alphabetical Series Set 1 | Reasoning

Q.1. JAF, JEF, JIF, JOF, ?

1. PIG

2. JET

3. JUF

4. JOF

Sol : Option 3

The middle letters which are vowels have an increasing trend of A, E, I, O, U and remaining letters have been retained as it is.So answer would be JUF.

Q.2. _ xx _ yx _ yy _ xy _ xxy

1. xxxyy

2. yxyxy

3. yyxxy

4. yyyxx

Sol : Option 3

The series is yxxy/yxxy/yxxy/yxxy. Thus, the pattern ‘yxxy’ is repeated.

Q.3. WXCD, UVEF, STGH, QRIJ, ?

1. OPKL

2. AYBZ

3. JIRQ

4. LRMS

Sol : Option 1

Start reading from CD, EF, GH, IJ, KL and then QR, ST, UV, WX, YZ and so on after splitting the groups.

Q.4. xy _ z _ xxyx _ px _ yxzpx _ yxzpx

1. xpzxx

2. yxyzx

3. yxzpx

4. zyxpy

Sol : Option 1

The series is xyxzpx/xyxzpx/xyxzpx/xyxzpx. Thus, the pattern ‘ xyxzpx’ is repeated.

Q.5. WYB, XUD, YQF, …

1. HZM

2. HCZ

3. ZMH

4. None of these

Sol : Option 3

Divide each member of series in this way: B D F H and so on (one gap) in ascending order, Y U Q M and so on (three gap) in descending order, WX Y Z and so on (no gap) in ascending order

Q.6. x_ p _ y _ _ pzy _ _ pzy

1. xyyyzz

2. xyzyzy

3. yxzyxy

4. yzxyxy

Sol : Option 4

The series is xypzy/ xypzy/ xypzy. Thus, the pattern ‘ xypzy’ is repeated.

Q.7. SAB, ?, QCD, PDD, OEF, NFF

1. CBT

2. ABR

3. BCT

4. RBB

Sol : Option 4

First letter in every group is in reverse alphabetical order i.e. SRQPON. The middle letter is in alphabetical order i.e ABCDEF and the last letter has pairs, BB, DD & FF.

Q8. _ x _ y _ xyxx _ yxy _ xyyx

1. xxxyy

2. xyxyy

3. yxyxy

4. yxyyx

Sol : Option 4

The series is yxx/yyx/ yxx/yyx/ yxx/yyx. Thus, the pattern yxx/yyx is repeated.

Q9.BAZ, DBY, FCX, ?

1. FXW

2. EFX

3. FEY

4. HDW

Sol : Option 4

The third, sixth and ninth letters are in the reverse order of the alphabet i.e.Z,Y, X, W. Ist fourth and seventh letters are going up with a gap of one letter and II, V and VIIIth are moved ahead one letter.

Q. 10 _ yz _ zx _ xyx _ z _ zxzxy

1. xyzyy

2. yyyzz

3. yxzyx

4. xyyzz

Sol : Option 1

The series is xyz/yzx/zxy /xyz/yzx/zxy . So, the letters change places in a cyclic manner.

Q1. a b _ b b c _ c _ a b _ a b _ b

(a) ccaac

(b) cbabc

(c) cacac

(d) bccab

Ans.(c)

Sol. The series is abc/b/bca/c/cab/a/abc/b.

Q2. _ a _ b _ a b a a _ b a b _ a b b

(a) aaabb

(b) ababb

(c) babab

(d) babba

S2. Ans.(d)

Sol. The series is baa/bba/baa/bba/baa/bb.

Thus, the pattern baa/bba is repeated.

Q3. c _ b a a _ a c a _ c a c a b _ a c a c _ b c a

(a) acbaa

(b) bbcaa

(c) bccab

(d) cbaac

S3. Ans.(a)

Sol. The series is cab/aa/cacab/cacab/aa/cacab/ca.

Thus, the pattern ‘cacab/cacab/aa’ is repeated.

Q4. Find the term which does not fit into the series:

1CV, 5FU, 9IT, 15LS, 17OR

(a) 5FU

(b) 15LS

(c) 9IT

(d) 17OR

Directions (5-15): In each of the following questions, a letter-number series is given with one or more terms missing as shown by (?). Choose the missing term out of the given alternatives.

Q5. KM5, IP8, GS11, EV14, ?

(a) BX17

(b) BY17

(c) CY17

(d) CY18

Q6. AZY, BWW, CTT, DQP, ?

(a) ENL

(b) ENK

(c) EJM

(d) VNU

Q7. GH, JL, NQ, SW, YD, ?

(a) EJ

(b) FJ

(c) EL

(d) FL

Q8. Z, W, S, P, L, I, E, ?

(a) B

(b) D

(c) F

(d) K

Q9. ejo,   tyd,   ins,   xch,   ?

(a) nrw

(b) mrw

(c) msx

(d) nsx

S9. Ans.(b)

Sol. There is a gap of four letters between the first and second, the second and third letters of each term, and also between the last letter of a term and the first letter of the next term.

Q10. Z, ?, T, ?, N, ?, H, ?, B

(a) W, Q, K, E

(b) W, R, K, E

(c) X, Q, K, E

(d) X, R, K, E

Q11. A, B, N, C, D, O, E, F, P, ?, ?, ?

(a) G, H, I

(b) G, H, J

(c) G, H, Q

(d) J, K, L

S11. Ans.(c)

Sol. The given series may be divided into 2 groups:

I. A, B, C, D, E, F, ?, ?

and II. N, O, P, ?

Clearly, the given series consists of two terms of I followed by one term of II.

The missing terms in I are G and H while the missing term in II is Q.

Q12. HAPPINESS, APPINESS, APPINES, PPINES, ?

(a) PINES

(b) PPINE

(c) PINE

(d) INES

S12. Ans.(b)

Sol. One letter from the beginning and one from the end of a term are removed, one by one, in alternate steps.

Q13. Z, S, W, O, T, K, Q, G, ?, ?

(a) N, C

(b) N, D

(c) O, C

(d) O, D

Q14. A, C, F, J, ?, ?

(a) L, P

(b) M, O

(c) O, U

(d) R, V

Q15. AC, FH, KM, PR, ?

(a) UW

(b) VW

(c) UX

(d) TV

S15. Ans.(a)

Sol.

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